Slope evidence · powers · linearity · polynomial derivatives

Power & Sum Rules

Measure local slopes of power functions, identify the reusable pattern, then differentiate polynomial terms without rebuilding the limit definition from scratch each time.

01 · Phenomenon

At x = 1, tiny secants on x², x³, and x⁴ approach slopes 2, 3, and 4.

The exponent seems to be showing up inside the slope. Is that only a coincidence at x = 1, or can one algebraic expression reproduce the local slopes everywhere?

02 · Slope sandbox
Slope-pattern laboratory

Measure first. Guess the derivative form second.

Choose a power function, squeeze a symmetric secant around one point, and watch its slope settle. Then test whether one candidate expression a·xᵇ reproduces the near-tangent slopes at several x-values.

Current evidencesecant slope ≈ 4.170

at x = 1.15 using points 0.45 units to either side. Shrink the width to make the local measurement more tangent-like.

Original function
Investigation cue

Try x = 1 first for several powers. Then move away from 1. Which part of your candidate seems to come from the old exponent, and which part seems to control how slope changes with x?

x = 1.15f(x) = x^3
Left point
(0.70, 0.34)

x − h

Measured slope
4.170

symmetric secant

Right point
(1.60, 4.10)

x + h

03 · Name the pattern

The derivative of a power is another power with one less degree.

For the polynomial powers explored in the sandbox, the slope measurements fit a compact rule: multiply by the old exponent, then reduce that exponent by one. This is the power rule.

The rule is a shortcut built on derivative structure, not a replacement for what a derivative means. It produces the function whose value gives the original function's local rate of change.

Power rule
ddx(xn)=nxn1\frac{d}{dx}(x^n)=nx^{n-1}

This lesson focuses on positive-integer powers used in polynomials. Broader versions of the power rule require attention to domains and how powers are defined.

04 · Formal structure

Polynomials become manageable because differentiation respects scaling and addition.

Power
ddx(xn)=nxn1\frac{d}{dx}(x^n)=nx^{n-1}

For the positive-integer polynomial powers explored here, the old exponent becomes a coefficient and the exponent decreases by one.

Constant multiple
ddx[cf(x)]=cf(x)\frac{d}{dx}[c f(x)]=c f'(x)

A fixed multiplier scales every local rate by the same factor.

Sum / difference
ddx[f(x)±g(x)]=f(x)±g(x)\frac{d}{dx}[f(x)\pm g(x)]=f'(x)\pm g'(x)

Addition and subtraction let derivative work distribute term by term.

Constant
ddx(C)=0\frac{d}{dx}(C)=0

A constant function does not change as x changes, so its local rate is zero.

05 · Worked derivative
Differentiate
f(x)=3x42x2+5x7f(x)=3x^4-2x^2+5x-7
01
3x42x2+5x73x^4-2x^2+5x-7

Start with the original polynomial.

01.5Differentiate each term independently

Use the power rule on the power terms, d/dx(x)=1 on the linear term, and d/dx(constant)=0.

02
3(4x3)2(2x)+5(1)03(4x^3)-2(2x)+5(1)-0

The original coefficients stay as multipliers.

02.5Multiply the coefficients and simplify

The derivative is already assembled term by term; now only arithmetic remains.

03
f(x)=12x34x+5f'(x)=12x^3-4x+5

This new function returns the local slope of f at each x.

06 · Common pitfall
The exponent does not stay the same.
wrong: x⁵ → 5x⁵power rule: x⁵ → 5x⁴

The old exponent does two jobs: it becomes a coefficient and the remaining power drops by one.

Term-by-term differentiation works for sums, not products.

If terms are added or subtracted, differentiate each term. If two changing functions are multiplied, (fg)(fg)' is not generally fgf'g'. That is why the Product Rule needs its own lesson.

07 · Application
Application · fresh polynomial

Differentiate the function.

f(x)=2x53x3+4x7f(x)=2x^5-3x^3+4x-7
Your derivative
xx+