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Lesson 2.5

IMPLICIT DIFFERENTIATION

What do you do when a graph isn't a function? When yy refuses to be isolated, we treat it like a hidden function and use the Chain Rule.

Explicit vs. Implicit

Until now, every equation has looked like y=3x2+2xy = 3x^2 + 2x. This is Explicit. yy is explicitly defined in terms of xx.

But look at the equation of a circle: x2+y2=25x^2 + y^2 = 25. yy is tangled up with xx. This is Implicit.

The Orbital Inspector
x² + y² = 25
Click & Drag on Circle

Live Calculation

Because we differentiated implicitly, the slope formula dy/dxdy/dx requires both the xx and yy coordinates to work.

x coordinate3.54
y coordinate3.54
Derivative (Slope)
-1.000
dydx=xy\frac{dy}{dx} = -\frac{x}{y}

The Golden Rule

When taking the derivative of an implicit equation, you differentiate both sides with respect to xx.

The catch: Because yy is really just a hidden function of xx, every time you take the derivative of a yy term, you must multiply it by dy/dxdy/dx (This is just the Chain Rule!).

Normal (x)

Differentiating xx terms is business as usual.

ddx(x2)=2x\frac{d}{dx}(x^2) = 2x

Implicit (y)

Differentiating yy requires the chain rule attachment.

ddx(y2)=2ydydx\frac{d}{dx}(y^2) = 2y \cdot \frac{dy}{dx}

Solving the Circle

Let's solve the math behind the interactive lab above:

1. Original Equation
x2+y2=25x^2 + y^2 = 25
2. Differentiate Both Sides
2x+2ydydx=02x + 2y \frac{dy}{dx} = 0
3. Isolate dy/dx
2ydydx=2x2y \frac{dy}{dx} = -2xdydx=xy\frac{dy}{dx} = -\frac{x}{y}

Notice that the final answer has both xx and yy in it. That's totally normal for implicit differentiation! It just means to find the slope, you need to know the specific point (x,y)(x, y) on the graph.