Special Relativity · 06 / 06

Relativistic Energy & Momentum

Energy and momentum form another invariant spacetime structure. Rest energy, kinetic energy, and momentum fit one relation that reduces to familiar Newtonian formulas only at low speed.

The learner question

What replaces Newtonian momentum and kinetic energy near light speed?

The Lorentz factor enters both momentum and total energy. Their values depend on frame, but the combination E2(pc)2E^2-(pc)^2 does not: it returns the object's rest energy squared in every inertial frame.

Energy-momentum invariant
E2=(pc)2+(mc2)2E^2=(pc)^2+(mc^2)^2

For a massive object at rest, p=0p=0 and the total energy is still E0=mc2E_0=mc^2.

Mass-shell lab

Move along one energy-momentum hyperbola.

γ = 1.667
rest energypcE
rest energy
89.88 PJ
total energy
149.79 PJ
kinetic energy
59.92 PJ
momentum
4.00 ×10⁸ kg·m/s
Speed v0.80 c
Rest mass m1.00 kg
energy-momentum idea
Momentum becomes p = γmv

At low speed γ ≈ 1, so Newtonian momentum reappears. Near c, the relativistic correction grows rapidly.

energy-momentum idea
Kinetic energy becomes (γ − 1)mc²

Its low-speed expansion approaches ½mv², but the exact relativistic expression remains valid all the way toward c.

energy-momentum idea
Rest mass is the invariant

The current energy-momentum values reconstruct 89.88 PJ of rest energy, matching mc² despite the boost.

momentum
p=gammamvp=\\gamma mv

frame-dependent vector quantity

total energy
E=gammamc2E=\\gamma mc^2

includes rest energy and kinetic energy

kinetic energy
K=(gamma1)mc2K=(\\gamma-1)mc^2

approaches ½mv² when v ≪ c

Mechanics bridge

Classical energy and momentum are the low-speed limit of this structure.

The conservation ideas from Mechanics survive; the formulas change so that conservation remains compatible with Lorentz symmetry.

Revisit Energy & Momentum
Transfer check

A massive particle is at rest in your frame. Its momentum is zero. What is its total energy?