Motion without causes

Kinematics

Describe where an object is, how its position changes, and how its velocity changes. The graphs and equations below are different views of the same motion.

The learner question

How can one moving object produce three different graphs?

Start with position. Velocity tells how quickly position changes. Acceleration tells how quickly velocity changes. Nothing new is being invented at each step; we are reading the same history at a different level of change.

Change ladder
positionvelocityacceleration

Each arrow means “rate of change with respect to time.”

Motion lab

Scrub one motion through time.

t = 2.40 s
0.0 mposition axis18.0 m
Positionx
7.20 m
Velocityv
3.00 m/s
Accelerationa
0.00 m/s²
timeconstant velocity
Position
x(t)
Velocity
v(t)
Acceleration
a(t)
Try a motion
Read the motion

Velocity stays constant, so the position graph is a straight line. Equal time intervals add equal displacements.

01

Position

Where is it?

A coordinate gives location relative to a chosen origin and positive direction.

xx
02

Displacement

How far did position change?

Displacement compares final and initial position. It can be positive, negative, or zero.

Deltax=xfxi\\Delta x = x_f - x_i
03

Velocity

How fast is position changing?

Velocity includes direction. Its sign tells which way position changes along the chosen axis.

vavg=fracDeltaxDeltatv_{avg} = \\frac{\\Delta x}{\\Delta t}
04

Acceleration

How fast is velocity changing?

Acceleration describes changing velocity. Negative acceleration does not automatically mean slowing down.

aavg=fracDeltavDeltata_{avg} = \\frac{\\Delta v}{\\Delta t}
Constant acceleration

Three equations, one model.

When acceleration is constant, these equations are linked descriptions of the same motion. Choose the one whose known quantities match the question rather than treating them as unrelated formulas.

Position from time
x=x0+v0t+frac12at2x = x_0 + v_0t + \\frac{1}{2}at^2

tracks position as time passes

Velocity from time
v=v0+atv = v_0 + at

tracks velocity as time passes

Time eliminated
v2=v02+2a(xx0)v^2 = v_0^2 + 2a(x-x_0)

connects velocity directly to displacement

Physics ↔ Algebra

Constant acceleration makes position quadratic.

x(t)=x0+v0t+12at2x(t) = x_0 + v_0t + \frac{1}{2}at^2

The squared time term is why the position graph bends into a parabola whenever acceleration is nonzero. The vertex can represent a physical turning point.

Open Patterns & Parabolas
Keep the representations connected
steeper position graphlarger |velocity|
velocity crosses zeroposition turning point
sloped velocity graphnonzero acceleration
flat velocity graphzero acceleration